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a^2-11a+5=0
a = 1; b = -11; c = +5;
Δ = b2-4ac
Δ = -112-4·1·5
Δ = 101
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{101}}{2*1}=\frac{11-\sqrt{101}}{2} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{101}}{2*1}=\frac{11+\sqrt{101}}{2} $
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